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@ -333,6 +333,7 @@ select combo_id as c_id,count(*) as sale_count from orders where status in(2,4)
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'children' => $children
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];
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}
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$combo_info['items']= $this->KeShiPaiXu($combo_info['items']);
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$pay_item_count += $combo->item_count;
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$true_price += $combo_info['price'];
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$combo_info['tags'][0]['text']=$comboItemCount. '个项目';
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@ -355,6 +356,10 @@ select combo_id as c_id,count(*) as sale_count from orders where status in(2,4)
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$items = DB::table('items')->whereIn('item_id', $item_ids)->where(['status' => 1])->get();
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$groupedData = [];
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foreach ($items as $item) {
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//判断套餐项目和自选项目是否冲突
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foreach ($combo_items as $comboitem) {
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if($comboitem['id']==$item->item_id) return \Yz::echoError1($item->name."已经存在，不可重复选择");
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}
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$item_price = bcadd($item_price, $item->price, 2);
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// $all_original_price+=$item->original_price;
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$all_original_price = bcadd($all_original_price, $item->original_price, 2);
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@ -378,6 +383,7 @@ select combo_id as c_id,count(*) as sale_count from orders where status in(2,4)
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if(isset($wj_flag) and $wj_flag==1){
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$item_price=number_format($item_price*$wj_zhekou, 2, '.', '') ;
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}
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//使用优惠券
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if(isset($coupon_id) and !empty($coupon_id)){
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if($item_price==0) return \Yz::echoError1("自选项目金额为0，无需使用优惠券");
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@ -391,6 +397,7 @@ select combo_id as c_id,count(*) as sale_count from orders where status in(2,4)
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'children' => $children
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];
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}
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$items_info['items']= $this->KeShiPaiXu($items_info['items']);
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$pay_item_count += count($items);
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$true_price += $items_info['price'];
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@ -691,4 +698,27 @@ select combo_id as c_id,count(*) as count from orders where status in(2,4) group
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return $true_price;
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}
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}
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public function KeShiPaiXu($data)
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{
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// 给定的科室顺序
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$sortedOrder = config('app.globals.KeShiPaiXu');
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// 创建一个科室到其在期望顺序中位置的映射
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$sortedOrderMap = array_flip($sortedOrder);
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// 使用 usort 函数进行排序
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usort($data, function($a, $b) use ($sortedOrderMap) {
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// 获取两个科室在期望顺序中的位置
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$posA = isset($sortedOrderMap[$a['keshi_name']]) ? $sortedOrderMap[$a['keshi_name']] : PHP_INT_MAX;
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$posB = isset($sortedOrderMap[$b['keshi_name']]) ? $sortedOrderMap[$b['keshi_name']] : PHP_INT_MAX;
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// 比较两个位置，确定排序
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return $posA - $posB;
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});
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return $data;
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}
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}
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yanzai
1 year ago